What is the result of mixing 100 gm of ice at - 10 ^ 0 * C into 100gm of water at 20 deg C into an iron vessel of mass 100gm? [Specific heat capacity of iron=0 1cal g * m ^ - 10 * c ^ - 1 specific heat capacity of water=1cal g * m ^ - 10 * c ^ - 1 latent heat of fusion of ice=80 cal/gm, specific heat capacity of ice= 0.5 cal gm¹°c) [3]

Answer :

Other Questions