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A farmer moves along the boundary of a square field of side 10 m in 40 s. What will be the magnitude of displacement of the farmer at the end of 2 minutes 20 seconds from its initial position ?

Answer :

littlerose
Case 1. Displacement = 10m
               Time = 40 sec
                Velocity = 10/40 = 0.25 m/sec
Case 2. Velocity = 0.25 m/sec
               Time = 2 min 20 sec = 140 sec
             Displacement = Velocity * Time 
                                       0.25 *140 = 35 m
............................................................................
SQ ABCD [figure][ diagonal AC ]
   he starts from A then in 140 sec he will reach opp. corner 
   displacement = AC i.e. x
 x^2= AB^2 +BC^2
 x^2 = 100+100
x^2=200 
x=√200
x=14.14m

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