Answer :
We have,
distance (s) = ?
Time = (t) = 4 seconds
Acceleration (a) = 2.5m/s²
Initial velocity (u) = 0 (the girl started the race)
So, by using second equation of motion we have,
s = ut + [tex] \frac{1}{2} [/tex]at²
s = 0*4 + [tex] \frac{1}{2}*2.5*4*4 [/tex]
s = 0 + 20
s = 20
So, the distance travelled by the girl is 20 m.
distance (s) = ?
Time = (t) = 4 seconds
Acceleration (a) = 2.5m/s²
Initial velocity (u) = 0 (the girl started the race)
So, by using second equation of motion we have,
s = ut + [tex] \frac{1}{2} [/tex]at²
s = 0*4 + [tex] \frac{1}{2}*2.5*4*4 [/tex]
s = 0 + 20
s = 20
So, the distance travelled by the girl is 20 m.
From second equation of motion,
S=ut+1/2at^2
S=0*4+1/2*2.5*4^2
S=1/2*2.5*16
S=2.5*8
S=20 m
S=ut+1/2at^2
S=0*4+1/2*2.5*4^2
S=1/2*2.5*16
S=2.5*8
S=20 m