Answer :
Let the North be represented by Y axis. The when the car turns left, it moves along the -ve x axis, towards West.
Let [tex]\vec{v1} = 50 \hat{j}\ kmph\ \ \ and,\ \vec{v2} = -50 \hat{i}\ kmph[/tex]
Change in velocity is = [tex]\vec{v2}-\vec{v1}=-50\hat{i}-50\hat{j}\ kmph[/tex]
Magnitude of change in velocity=[tex]\sqrt{50^2+50^2}=50\sqrt{2}[/tex]
Direction of the change in velocity = South west , 45 deg. from South towards West.
Let [tex]\vec{v1} = 50 \hat{j}\ kmph\ \ \ and,\ \vec{v2} = -50 \hat{i}\ kmph[/tex]
Change in velocity is = [tex]\vec{v2}-\vec{v1}=-50\hat{i}-50\hat{j}\ kmph[/tex]
Magnitude of change in velocity=[tex]\sqrt{50^2+50^2}=50\sqrt{2}[/tex]
Direction of the change in velocity = South west , 45 deg. from South towards West.