Answer :
It is impossible
Proof:
Let x, y, z be 3 required odd numbers
x+y+z=30
Odd no. +odd no. =even no.
So x+y=even
z+even no. =30 (which is even no.)
z+even no. =even no.
z=even no. - even no.
So, z=even no...
But.... Z is odd no.
Hence, sum of 3 odd numbers can never be 30 or any even number.
The sum of
three odd numbers gives an odd number
So, the sum of 3 given odd numbers doesnt results 30
So, it is an impossible factor
here we can't use 3! too
because 3! [3×2×1] results a even number 6
so we cant use it.
If there will be an allowance of factorials, then the answers will be
3! + 15 + 9 =30
3! + 11 + 13 = 30
So, the sum of 3 given odd numbers doesnt results 30
So, it is an impossible factor
here we can't use 3! too
because 3! [3×2×1] results a even number 6
so we cant use it.
If there will be an allowance of factorials, then the answers will be
3! + 15 + 9 =30
3! + 11 + 13 = 30