Answer :
first factorise 12=2x2x3 , then factorise 6=2x3
second, given 4√12 x 7√6 can be written as 4√2x2x3 * 7√2x3
and one more step , multiple like this 4x7√2x2x3x3x2
one 2 and one 3 comes out and one 2 is left inside root
4x7x2x3√2=168√2
second, given 4√12 x 7√6 can be written as 4√2x2x3 * 7√2x3
and one more step , multiple like this 4x7√2x2x3x3x2
one 2 and one 3 comes out and one 2 is left inside root
4x7x2x3√2=168√2
Concept:
This question requires us to have knowledge of how to prime factorise a number.
Prime factorization or integer factorization of a number is breaking a number down into the set of prime numbers which multiply together to result in the original number.
Given:
The below equation is given
[tex]4\sqrt{12} *7\sqrt{6}[/tex]
To find:
We need to find the value of the above equation.
Solution:
Now, we can factorise
[tex]4\sqrt{12}*7\sqrt{6}[/tex]
⇒[tex]2*2*\sqrt{2}*\sqrt{2}*\sqrt{3}*7*\sqrt{3}*\sqrt{2}[/tex]
⇒[tex]4*7*\sqrt{2*2*3*3*2}[/tex]
⇒[tex]4*7*2*3*\sqrt{2}[/tex]
⇒[tex]168\sqrt{2}[/tex]
Therefore, the value of the equation [tex]168\sqrt{2}[/tex].