Answer :
area of the enclosed isosceles triangle: Asector = R²/2 (θ - sin(θ))
let the sector area equal to 1/3 of the circle area:
R²/2 (θ - sin(θ)) = πR²/3
2π/3 = θ - sin(θ)
θ ≈ 2.605325674600903 radians (149.2741654º)
The lines should be ≈ 1.854524592 units from the center of the circle
let the sector area equal to 1/3 of the circle area:
R²/2 (θ - sin(θ)) = πR²/3
2π/3 = θ - sin(θ)
θ ≈ 2.605325674600903 radians (149.2741654º)
The lines should be ≈ 1.854524592 units from the center of the circle