Answer :
let the shorter side is x ,then larger side is x + 30
from pythagoras theorem (both side are perpendicular)
60^2 = x^2 + (x + 30)^2
3600 = 2x^2 + 60x + 900
x^2 + 30x - 2700 = 0
x = -15 + 5√63,or -15 - 5√63
length of the side can not be negative ,hence
x = -15 + 5√63 (shorter side)
x + 30 = 15 + 5√63 (larger side)
hence shorter side is -15 + 5√63 and larger side is 15 + 5√63
from pythagoras theorem (both side are perpendicular)
60^2 = x^2 + (x + 30)^2
3600 = 2x^2 + 60x + 900
x^2 + 30x - 2700 = 0
x = -15 + 5√63,or -15 - 5√63
length of the side can not be negative ,hence
x = -15 + 5√63 (shorter side)
x + 30 = 15 + 5√63 (larger side)
hence shorter side is -15 + 5√63 and larger side is 15 + 5√63