siddhartaTrivedi
Answered

If the speed of light is 3.0 * 10^{8} m s^{-1} , calculate the distance covered by light in 2.00 ns.

NCERT Class XII
Chemistry - Main Course Book I

Chapter 1. Some Basic Conpepts of Chemistry

Answer :

kaushikravikant
Speed of light=3x10^8m/s
time=2ns=2x10^-9s
distance traveled=timexspeed
3x10^8 x 2 x10^-9
6x10^-1=0.6m

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