Hi ,
write 81 ,216 , 32 ,225 as product of the prime.
1 ) 81 = 3 × 3 × 3 × 3
2 ) 216 = 2 × 2 × 2 × 3 × 3 × 3
3 ) 32 = 2 × 2 × 2 × 2 × 2
4 ) 225 = 3 × 3 × 5 × 5
Now ,
i ) fourth root of 81 = ( 81 ) 1/4 = ( 3^4 ) 1/4 = 3 ^ (4 × 1/4 ) = 3
ii) ∛216 = ( 216 ) 1/3 = ( 2³ × 3³ )^ 1/3 = [ ( 2 × 3 )³ ]^ 1/3 = (2 × 3 ) = 6
iii ) fifth root 0f 32 = ( 32 )^1/5 = ( 2^5 ) ^1/5 = 2
iv ) √225 = √ ( 3 × 3 ) × ( 5 × 5 ) = 3 × 5 = 15
Given problem is ,
fourth root of 81 - 8 ∛216 + 15 fifth root of 32 + √225
= 3 - ( 8 × 6 ) + ( 15 × 2 ) + 15 [ put from ( i ) to ( iv ) values ]
= 3 - 48 + 30 +15
= 48 - 48
= 0
I hope it helps you.
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