Answer :
There are 50 gms of glucose in water (1kg).
Kf = 1.853 deg K kg/mol
molecular mass of glucose C6 H12 O6 = 180
depression in freezing point: 1.853 * 50/180 = 0.514 deg K
freezing point: 272.635 deg K
Kf = 1.853 deg K kg/mol
molecular mass of glucose C6 H12 O6 = 180
depression in freezing point: 1.853 * 50/180 = 0.514 deg K
freezing point: 272.635 deg K