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Two cars leave with a time gap of 1 min from the same point. They move with an acceleration of 0.2m/s^2.how long after the departure of the second car does the distance between them become equal to three times its value , when the second car just starts???????
Please give the answer

Answer :

ur physics teacher can give the ans in a better way

Answer:

2 min

Explanatiton:

let u for both the cars be =0

s1=ut+1/2at^2

=1/2(0.2)t^2

=0.1(t^2)-----------(2)

s2=1/2(0.2) (t-60)^2

 =t^2+120t+3600   ------------(1)

(1)=3*(2)

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