If tanA= 1/2 , tanB=1/3. Using tan (A+B)= tanA
+tan B/1-tanA +tanB, Prove that (A+B)=45
Answer:
It is proved that [tex]A+B=45[/tex]
Step by Step Explanation:
As we know [tex]tan(A+B) = \frac{ tanA + tanB}{1 - tanAtanB}[/tex]
Step 1:
Given that [tex]tanA = \frac{1}{2}[/tex] and [tex]tanB = \frac{1}{3}[/tex]
[tex]tan(A+B) =[/tex] [tex]\frac{ tanA + tanB}{1 - tanAtanB}[/tex]
[tex]={\Large } \frac{\frac{1}{2} + \frac{1}{3} }{1-\frac{1}{2} \frac{1}{3} }[/tex]
[tex]=\frac{5}{6} /\frac{5}{6}[/tex]
[tex]=1[/tex]
Step 2:
[tex]\therefore[/tex][tex]A+B = 45[/tex]
Hence proved.
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