The number of values of x ∈ [0,2] at which f(x) = |x-1/2|+|x-1|+Tan x is not differentiable at A) 0 B) 1 C) 2 D) 3 Given the answer is option D please explain me how
|x-1/2| is not differentiable at x-1/2 =0 => x = 1/2 |x-1| is not differentiable at x-1 = 0 => x = 1 Tanx is not differentiable at pi/2 (Tanx is not differentiable where its value is ∞ or -∞) hence in [0,2] f(x)is not differentiable at three points
