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If [tex]x = 2y + 6[/tex] Find the valye of [tex]x^{3} - 8y^{3} -36 xy- 216[/tex]   ....

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Mathexpert
Given that x = 2y + 6
⇒ x - 2y - 6 = 0
⇒ x + (-2y) + (-6) = 0
We know that, if a + b + c = 0 then [tex]a^3 + b^3 + c^3 = 3abc[/tex]
⇒[tex]a^3 + b^3 + c^ 3 - 3abc = 0[/tex]
⇒The value of  [tex]x^3 - 8y^3 - 216 - 36xy[/tex]
[tex]x^3 + (-2y)^3 + (-6)^3 - 3(x)(-2y)(-6) = 0[/tex]

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