Answer :

Mathexpert
Given polynomial is 
f(x) = [tex]2x^3 -6x^2 +5x+4[/tex]

(x - 2) is a factor of the given polynomial only if f(2) = 0

f(2) = [tex]2(2)^3 -6(2)^2 +5(2) + 4[/tex]

 = 2(8) - 6(4) + 10 + 4

= 16 - 24 + 24

= 16

So, (x – 2) is not a factor of [tex]2x^3 -6x^2 +5x+4[/tex]

vikaskumar0507
for (x - 2) to be factor of (2x³-6x²+5x+4) , at x = 2  ,2x³-6x²+5x+4 should be zero, put x = 2 
 2*2³-6*2²+5*2+4
= 16-24+10+4
= 6 ≠ 0
hence (x-2) is not a factor of (2x³-6x²+5x+4)

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