Answer :
There is a simple formula to solve these questions :-
[tex]T=2 \pi \sqrt{ \frac{L}{g} } [/tex]
Where T= Time Period in seconds
L= Length of the Pendulum in meters
g= Value of acceleration due to gravity in m/s^2.
So, putting the values respectively in the answer, we get :-
1 = 2 pi root [L/19.8] = 0.9929 meters ~ 1 meter.
I don't really know of velocity, but it can be related with mgh = 1/2 mv^2
Well.. try it :-)
[tex]T=2 \pi \sqrt{ \frac{L}{g} } [/tex]
Where T= Time Period in seconds
L= Length of the Pendulum in meters
g= Value of acceleration due to gravity in m/s^2.
So, putting the values respectively in the answer, we get :-
1 = 2 pi root [L/19.8] = 0.9929 meters ~ 1 meter.
I don't really know of velocity, but it can be related with mgh = 1/2 mv^2
Well.. try it :-)