Answer :
[tex] \frac{dv}{dt} = 6-3v \\ \frac{dv}{6-3v} = dt \\ ln(6-3v)/(-3) = t + c [/tex]
At t=0, v=0
Therefore c = ln(6)
On simplifying it gives [tex]v = 2(1-e^{-3t})[/tex]
At t=0, v=0
Therefore c = ln(6)
On simplifying it gives [tex]v = 2(1-e^{-3t})[/tex]