Answer :
salary of 7 technicians=7×12000=84000
8000x = 84000 + (x - 7)(6000)
8x = 84 + (x - 7)(6)
8x = 84 + 6x - 42
2x = 42
x = 42 / 2
=21
8000x = 84000 + (x - 7)(6000)
8x = 84 + (x - 7)(6)
8x = 84 + 6x - 42
2x = 42
x = 42 / 2
=21
the average salary of all the workers in a workshop is 8000. the
salary of 7 technicians is 12000 and the rest is 6000 . how many
workers are there in the workshop
Solution:
Let the total Number of Workers in a Workshop = X
Average Salary Of X workers = 8000.
therefore Sum of Salary of all Workers = Number Of Workers * Average salary
= X * 8000
= 8000X
Therefore , According to Question , 7 technicians have 12000 salary while rest of the workers have 6000 salary .
Hence,
12000 * 7 + (X - 7 )*6000 = 8000X
=> 84000 + 6000X - 42000 = 8000X
=> 42000 + 6000X = 8000X
=> 42000 = 8000 X - 6000 X
=> 42000 = 2000 X
=> 42000/2000 = X
=> 21 = X
=> X =21
hence Total Number of Workers = 21
Hope This helps You !!!
Thank YoU!!
Solution:
Let the total Number of Workers in a Workshop = X
Average Salary Of X workers = 8000.
therefore Sum of Salary of all Workers = Number Of Workers * Average salary
= X * 8000
= 8000X
Therefore , According to Question , 7 technicians have 12000 salary while rest of the workers have 6000 salary .
Hence,
12000 * 7 + (X - 7 )*6000 = 8000X
=> 84000 + 6000X - 42000 = 8000X
=> 42000 + 6000X = 8000X
=> 42000 = 8000 X - 6000 X
=> 42000 = 2000 X
=> 42000/2000 = X
=> 21 = X
=> X =21
hence Total Number of Workers = 21
Hope This helps You !!!
Thank YoU!!