Answer :
Use the distance formula
First triangle:
(0,0) (0,8) (6,0)
the 3 sides are
[tex] \sqrt{ (0-0)^{2} + (0-8)^{2} } = 8[/tex]
[tex] \sqrt{ (0-0)^{2} + (0-6)^{2} } = 6[/tex]
[tex] \sqrt{ (0-6)^{2} + (8-0)^{2} } = 10[/tex]
Perimeter = 24
Second Triangle:
(0,0) (9,3) (1,-3)
[tex] \sqrt{ (0-9)^{2} + (0-3)^{2} } =3\ \sqrt{10}[/tex]
[tex] \sqrt{ (0-1)^{2} + (0-(-3))^{2} } = \sqrt{10}[/tex]
[tex] \sqrt{ (9-1)^{2} + (3-(-3))^{2} } = 10[/tex]
Perimeter = [tex]10 + 4 \sqrt{10} [/tex]
First triangle:
(0,0) (0,8) (6,0)
the 3 sides are
[tex] \sqrt{ (0-0)^{2} + (0-8)^{2} } = 8[/tex]
[tex] \sqrt{ (0-0)^{2} + (0-6)^{2} } = 6[/tex]
[tex] \sqrt{ (0-6)^{2} + (8-0)^{2} } = 10[/tex]
Perimeter = 24
Second Triangle:
(0,0) (9,3) (1,-3)
[tex] \sqrt{ (0-9)^{2} + (0-3)^{2} } =3\ \sqrt{10}[/tex]
[tex] \sqrt{ (0-1)^{2} + (0-(-3))^{2} } = \sqrt{10}[/tex]
[tex] \sqrt{ (9-1)^{2} + (3-(-3))^{2} } = 10[/tex]
Perimeter = [tex]10 + 4 \sqrt{10} [/tex]
Answer:
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Step-by-step explanation: