Answer :
Reena has pens and pencils which together are 40 in
number. If she has five more pencils and five less pens, then the number
of pencils would become four times the number of pens. Find the
original number of pens and pencils. Answer in detail.
Solution :
Number of Pens and Pencils = 40
Let the number of Pens = x
and let Number of Pencils = y
therefore ,
x + y = 40
=> y = 40 - x ............................. (1)
According to Question ,
y + 5 = 4 ( x - 5 )
y +5 = 4*x - 4*5
y + 5 = 4x - 20
y = 4x -20 -5
y = 4x - 25 ...................................(2)
from 1 and 2 , we get
4x - 25 = 40 - x
4x = 40 - x + 25
4x + x = 40 + 25
5x = 65
x = 65/5
x = 13
Therefore Number of Pens = 13
Substitute the value of x in 1 , we get
y = 40 - x
y = 40 - 13
y = 27
Therefore Number of Pencils = 27
Hope this helps You!!!
Solution :
Number of Pens and Pencils = 40
Let the number of Pens = x
and let Number of Pencils = y
therefore ,
x + y = 40
=> y = 40 - x ............................. (1)
According to Question ,
y + 5 = 4 ( x - 5 )
y +5 = 4*x - 4*5
y + 5 = 4x - 20
y = 4x -20 -5
y = 4x - 25 ...................................(2)
from 1 and 2 , we get
4x - 25 = 40 - x
4x = 40 - x + 25
4x + x = 40 + 25
5x = 65
x = 65/5
x = 13
Therefore Number of Pens = 13
Substitute the value of x in 1 , we get
y = 40 - x
y = 40 - 13
y = 27
Therefore Number of Pencils = 27
Hope this helps You!!!
Let, the no. Of pens be x and no. Of pencils be y. x+y=40--------1 Acc. To ques 4(x-5)=y+5 4x-20=y+5 4x-y=25---------2 From 1 and 2 x+y=40 4x-y=25 ――――――― 5x=65 x=13 Substitute the value of x in eq.1 x+y=40 13+y=40 y=27 So, pens be 13 and pencils be 27..