Answer :
20 boys and girls sold tickets for a funfair. Each ticket was sold
at $5.Each boy sold 5 tickets and each girl sold 3 tickets. The amount
collected by the boys was $20 more than the amount collected by the
girls. Find
a) how many girls were there in the group
b) how many tickets were sold altogether?
Solution:
No Of Boys = 20
Let No Of Girls = x
No. Of Tickets sold by One Boy = 5
Therefore Number of tickets Sold by 20 Boys = 5*20
= 100
Cost of one Ticket = $5
therefore Cost of 100 Tickets = $5*100
= $500
No. Of tickets Sold by One Girl = 3
Therefore , No of tickets Sold By x Girls = 3*x
= 3x
Therefore Cost of 3x tickets = $5*3x
= $15x
According to Problem ,
$15x = $500 - $20
$15x= $480
x=$480/$15
x= 32
Hence The Number of Girls is 32 .
b) therefore total Number of Tickets sold = 100 + 3x
= 100 + 3*32
= 100 + 96
=196
Hope This Helps You!!!
a) how many girls were there in the group
b) how many tickets were sold altogether?
Solution:
No Of Boys = 20
Let No Of Girls = x
No. Of Tickets sold by One Boy = 5
Therefore Number of tickets Sold by 20 Boys = 5*20
= 100
Cost of one Ticket = $5
therefore Cost of 100 Tickets = $5*100
= $500
No. Of tickets Sold by One Girl = 3
Therefore , No of tickets Sold By x Girls = 3*x
= 3x
Therefore Cost of 3x tickets = $5*3x
= $15x
According to Problem ,
$15x = $500 - $20
$15x= $480
x=$480/$15
x= 32
Hence The Number of Girls is 32 .
b) therefore total Number of Tickets sold = 100 + 3x
= 100 + 3*32
= 100 + 96
=196
Hope This Helps You!!!