A train travels the first 15km at uniform speed of 30km/h next 10 km at uniform speed of 20 km/h and final 75 km at uniform speed of 50 km/h . the average speed for the entire journey of the train ?

Answer :

40 km\h
d1=15km s1=30km\h
d2=10km s2=20km\h
d3=75km s3=50km\h

total time taken=t1+t2+t3
=0.5+0.5+1.5=2.5
speed =distance\time
100\2.5=40km\h

D1=15km

D2=75km

D3=10km

S1=30kmh-1

S2=50kmh-1

S3=10kmh-1

Avg. Speed=total distance÷total time taken

T1=0.5hr

T2=0.67hr

T3=0.5hr

Let the avg.speed be s.

S=15+75+10÷0.5+0.5+0.67

S=100÷1.67

Therefore,s=40kmperhr

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