Answer :
given that
ABCD is a quadrilateral
we know that
sum of all angles in a quadrilateral =360
A+B+C+D=360
2x+4+2x-13+3x+11+4x-5=360
11x-3=360
11x=360+3
11x=363
x=363/11
x=33
A=2x+4=2(33)+4=66+4=70
B=2x-13 = 2(33)-13 = 66-13 = 53
C=3X+11 = 3(33)+11 = 99+11 = 110
D=4X-5 = 4(33)-5 = 132-5 = 127
ABCD is a quadrilateral
we know that
sum of all angles in a quadrilateral =360
A+B+C+D=360
2x+4+2x-13+3x+11+4x-5=360
11x-3=360
11x=360+3
11x=363
x=363/11
x=33
A=2x+4=2(33)+4=66+4=70
B=2x-13 = 2(33)-13 = 66-13 = 53
C=3X+11 = 3(33)+11 = 99+11 = 110
D=4X-5 = 4(33)-5 = 132-5 = 127
Hence, all the angles of the quadrilateral ABCD are 70•, 53°, 110° and 127°
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