Answer :
We know the algebraic identity
(x+a)(x+b)=x^2+(a+b)x+ab
If x=1 then
(1+a)(1+b)=1+(a+b)+ab----(1)
Given
m+n+mn=118
Add 1 both sides
1+m+n+mn=118+1
From (1)
(1+m)(1+n)=119
(1+m)(1+n)=17×7
(1+m)(1+n)=(1+16)(1+6)
Compare bothsides
Therefore
m=16,n=6
(x+a)(x+b)=x^2+(a+b)x+ab
If x=1 then
(1+a)(1+b)=1+(a+b)+ab----(1)
Given
m+n+mn=118
Add 1 both sides
1+m+n+mn=118+1
From (1)
(1+m)(1+n)=119
(1+m)(1+n)=17×7
(1+m)(1+n)=(1+16)(1+6)
Compare bothsides
Therefore
m=16,n=6