yaha
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a solid sphere of radius r is melted to recast into  27 solid spheres of radius r find r and ratio of surface areas  of two spheres

Answer :

anamika
4/3/[tex] \pi [/tex][tex] r^{3} [/tex]=4/3[tex] \pi[/tex][tex] R^{3} [/tex]
[tex] r^{3} [/tex]=27[tex] R^{3} [/tex]
r=3R
surface area of 1circle/surface area of 2 circle=
[tex] r^{2} [/tex]=[tex] R^{2} [/tex]
9R*R=R*R
9:1

lipi
RADIUS OF 1SPHERE=r
"              "    2SPHERE=R
SO FOR 27 SPHERE=27R
SO r3=27R3
S0 r=3R
NOW SURFACE AREA
4/3 PI r2=4/3 PI R2
9R2=R2
SO THE RATIO IS 9:1

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