sunilOza
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Wat must be subractedfrom 4x​3+16x2-x+5 to obtain a polynomial which is exactly divisible by x+5

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parasakthi
i have divided 4[tex] x^{3} [/tex]+16[tex] x^{2} [/tex]-x+5  with x+5 in that pic , we got -90 reminder so we need to subtract -90 from 4[tex] x^{3} [/tex]+16[tex] x^{2} [/tex]-x+5

4[tex] x^{3} [/tex]+16[tex] x^{2} [/tex]-x+5 -(-90) = 4[tex] x^{3} [/tex]+16[tex] x^{2} [/tex]-x +95

I HOPE THIS HELPS , OF COURSE MY HANDWRITING IS HORRIBLE  :P


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