Answer :
Let the digit in units place be x
The digit in tens place should be 8-x (as sum of the digits is 8)
The number is 10(8-x)+x = 80-9x
If 8 is added to the number, the digits are reversed.
80-9x + 8 = 10(x) + 8-x
88 - 9x = 9x + 8
18x = 80
x =
Something is wrong with the question
The digit in tens place should be 8-x (as sum of the digits is 8)
The number is 10(8-x)+x = 80-9x
If 8 is added to the number, the digits are reversed.
80-9x + 8 = 10(x) + 8-x
88 - 9x = 9x + 8
18x = 80
x =
Something is wrong with the question