a ball is thrown vertically upward with an initial velocity of 49 m p s . calculate a) maximum height attained b) time taken by it before it reaches the ground again ( g = 9.8 m p s square )
Final velocity(v)=49 metre per second initial velocity(u)=0 g=9.8 metre per second² h=? v²=u²+2gh ⇒v²=2gh ⇒h=v²÷2g ⇒h=49×49/9.8×2 ⇒h=122.4999999 metres Hence, the maximum height reached will be 122.4999999 metres.
