Answer :

bipsii
considering 1 and the number itself as the divisors.....d(p^5) is 6(1,p,p^2,p^3.p^4,p^5)....d(6) is 4,d(4) is 3 and d(3) is 2.Therefore d(d(d(p^5)))=2
d[d[d[5+1]]]
d[d[d∧6]]
d[d[6+1]]
d[d∧7]
d[d∧7+1]
d[8]
d[2∧3]
d[3+1]
d[4]
d[2∧2]
d[2+1]
d[3]
2











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