Answer :

Rakesh
In this kind of equation you can just skip the square as it changes nothing here. It means that we can solve it like this: 

[tex](y-2)^2=0 \\ y-2=0\\y=2[/tex]

Ok, let's check if it adds up now: 

[tex]y=2 \\ (2-2)^2=0 \\ 4-4=0 \\ 0=0[/tex]

Cheers! 
lipi
(y-2)^{2} =0^{2} 
so y-2=0
y=2

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