Answer :

[tex]\frac{1}{ \sqrt{7}- \sqrt{3} } =\frac{1}{ \sqrt{7}- \sqrt{3} } * \frac{ \sqrt{7}+ \sqrt{3} }{ \sqrt{7} + \sqrt{3} } = \frac{ \sqrt{7} + \sqrt{3} }{( \sqrt{7}+ \sqrt{3}) ^{2} } = \frac{ \sqrt{7}+ \sqrt{3} }{(7+3)} =\frac{ \sqrt{7}+ \sqrt{3} }{10} [/tex] 
badhri
1/√7-√3 * (√7+√3)/√7+√30
=(√7+√3)/(√7)²-(√3)²
=(√7+√3)/ (7-3)
=(√7+√3) /4 

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