Answer :
using formula [tex]s = ut + 1/2at ^{2} [/tex]
where s= distance covered u is initial velocity which is 0 as the motion is started from rest a is acceleration and t is time which is 60 sec
using formula s = 0.60 + 1/2 .10 . 60 .60
⇒s = 18000 mtrs is the distance covered.
where s= distance covered u is initial velocity which is 0 as the motion is started from rest a is acceleration and t is time which is 60 sec
using formula s = 0.60 + 1/2 .10 . 60 .60
⇒s = 18000 mtrs is the distance covered.