Answer :
let cost of one cycle be x and other cycle be y
so x + y = 900 ⇒ y = 900 - x
given (y × 125)/2 - ( x × 80)/100 = 90
((900 - x) × 125)/2 - ( x × 80)/100 = 90
solving x we get x = 505
so cost of cycles = rs 505 and 900 - 505 = rs 395
so x + y = 900 ⇒ y = 900 - x
given (y × 125)/2 - ( x × 80)/100 = 90
((900 - x) × 125)/2 - ( x × 80)/100 = 90
solving x we get x = 505
so cost of cycles = rs 505 and 900 - 505 = rs 395