Answer :
so given height of a right angle triangle = a - b
given base of a right angle triangle = a +b
use Pythagoras theorem we get
hypotenuse = √{(a - b)² + (a + b)²}
= √{2(a² + b²)}
so sin θ=
(a - b)/√{2(a² + b²)}
given base of a right angle triangle = a +b
use Pythagoras theorem we get
hypotenuse = √{(a - b)² + (a + b)²}
= √{2(a² + b²)}
so sin θ=
(a - b)/√{2(a² + b²)}
given height =a-b given base=a square + b square using phythogorus theorum sin = a-b/root{2(a square + b square)}