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An electron is projected, with an initial speed of [tex] v_{i}=3.10^{5} m s^{-1} [/tex], directly towards a proton that is essentially at rest. If the electron is initially a great distance from the proton, at what distance from the proton is its speed instantaneously equal to twice its initial value? Express your answer in meters.

Answer :

i think d= 1.76*10^(-9) m
now it is correct

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