A man standing on a railway bridge which is 180 m long . He find that a train crosses that bridge in 20 seconds but himself in 8 seconds. Find the speed of the train?

Answer :

Let x = length of train . Distance = 180 m + x speed of train while crossing bridge = d/t = 180+ x)/20 = 9 + x/20 , speed of train while crossing the man = d/t = x/8 a/q .................. 9 + x/20 = x/8 => 9 = x/8-x/20=> 9= (5x-2x)/40 => 9*40/2=x => x= 180 m now speed of train = 180/8 m/s = 22.5m/s

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