Answer :

sprashant978
put x=4 in both equation
and as the remainder is same so both will be equal 
so, 64a+48-3=128+20-a
      64a+a=148-45
      65a=103
       a=1.58
karthik4297
(ax^3+3x^2-3)/(x-4) = (2x^3+5x-a)/(x-4)
or, ax^3+3x-3=2x^3+5x-a
or, now when we put x=1(any constant),then
a+3-3=2+5-a
or, 2a=7
a = 7/2

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