Answer :

if there is no restriction on the method used, use the quadratic equation method.
it is simple and quick.

f(x) = x² + 8x + 6 = 0
 x = [ -8 +- √(8² - 4*6)  ] / 2  =  -4 +- √10
zeros are -4 - √10 and -4 +√10

[tex]f(x)=x^2+8x+6\\\\a=1;\ b=8;\ c=6\\\\\Delta=b^2-4ac\to\Delta=8^2-4(1)(6)=64-24=40\\\\x=\frac{-b\pm\sqrt\Delta}{2a}\\\\\sqrt\Delta=\sqrt{40}=\sqrt{4\times10}=\sqrt4\times\sqrt{10}=2\sqrt{10}\\\\x=\frac{-8\pm2\sqrt{10}}{2(1)}=-4\pm\sqrt{10}[/tex]

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