Answer :
[tex]\begin{array}{lll}(x^3-4x^2+2x+1) & : & (x-1) = x^2 - 3x -1 \\\underline{-x^3 + x^2} & & \\
\qquad -3x^2 +2x+1& & \\\qquad \ \ \underline{3x^2 - 3x} & &\\\qquad \qquad\ \ \ -x+1 & & \\
\qquad \qquad\ \ \ \ \ \underline{x-1} & & \\\qquad \qquad \qquad R=0\end{array}\\\\\\(x^3-4x^2+2x+1):(x-1)=x^2-3x-1[/tex]