Answer :
% of N = 1.4*M(V-V1)/m
M = molarity of HCl solution
V = volume of HCl in ml
V1 = volume of HCl neutralise by NaOH in ml
m = weight of compound taken in gm.
% of N = 1.4*1*11.6/1.15 (for HCl normality = molarity)
% of N = 14.12
M = molarity of HCl solution
V = volume of HCl in ml
V1 = volume of HCl neutralise by NaOH in ml
m = weight of compound taken in gm.
% of N = 1.4*1*11.6/1.15 (for HCl normality = molarity)
% of N = 14.12