Answer :
see diagram enclosed
Let angle EAP = angle BAP = x (AP bisector)
Let angle RBP = angle PBA = y BP is bisector
angle EAB + angle ABR = 180 degrees as AE and BR are parallel
2 * x + 2 * y = 180 deg x + y = 90
angle APB = 180 - x - y in trianle APB
angle APB = 180 - 90 = 90 deg
Let angle EAP = angle BAP = x (AP bisector)
Let angle RBP = angle PBA = y BP is bisector
angle EAB + angle ABR = 180 degrees as AE and BR are parallel
2 * x + 2 * y = 180 deg x + y = 90
angle APB = 180 - x - y in trianle APB
angle APB = 180 - 90 = 90 deg
Step-by-step explanation:
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