0.01
Step-by-step explanation:
[tex]\frac{(125)^{-2/3} }{8^{2/3} }[/tex] is the given equation.
Now, As we know, [tex]a^{-b} = \frac{1}{a^{b} }[/tex]
Also, 125 = 5 x 5 x 5 = [tex]5^{3}[/tex]
and , 8 = 2 x 2 x 2 = [tex]2^{3}[/tex]
So, the equation becomes : [tex]\frac{(5^{3}) ^{-2/3} }{(2^{3}) ^{2/3} }[/tex]
On solving further,
⇒ we get [tex]\frac{5^{-2} }{2^{2} } = \frac{1}{5^{2}\times 2^{2} } = \frac{1}{25 \times 4} = \frac{1}{100}[/tex]
= 0.01
