yoshi
Answered

 could i get an answer for this question :
√sec²Ф+cosec²Ф =     ?? 

Answer :

kkpc22803
root(1/cos^2fi+1/sin^2 fi)=root(sin^2fi+cos^2fi)/sin^2fi cos^2 fi

hence=  1/sinfi cos fi= 1/1/2sin2fi= 2 coec2fi
annumalekar
let  : rt(sec^2fi+cosec^2fi)=X
X^2=sec^2fi+cosec^2fi
     =1/cos^2fi+1/sin^2fi
     =(sin^2fi+cos^2fi)/(sin^2fi cos^2fi)
     =1/(sin^2fi cos^2fi)
 X^2=sec^2fi cosec^2fi
 X = sec fi. cosec fi

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