perimeter is 68cm we know that diagonals of a rhombus bisect each other at 90 degrees so acc. to Pythagoras theorm AC^2 = AB^2 + BC^2 = 64 + 225 = 289 AC = 17cm So perimeter = 17*4 = 68cm
The diagnols of a rhombus bisect each other and are perpendicular to each other therefore side of rhombus=root of (15^2+8^2)=root of (289)= 17 therefore perimeter of square=68
