Answer :
let x be the √6√6√6···
x=√6√6√6√6√6√6········
x²={√6√6√6√6√6....}²
x²=6√6√6√6√6√6·····
x²=6×x
x²/x=6
x=6
x=√6√6√6√6√6√6········
x²={√6√6√6√6√6....}²
x²=6√6√6√6√6√6·····
x²=6×x
x²/x=6
x=6
[tex] Let\ x =6 \\ \\ y = \sqrt{x \sqrt{x \sqrt{x \sqrt{x....} } } } \\ \\ y = \sqrt{x\ \ \ ( \sqrt{x \sqrt{x \sqrt{x \sqrt{x....} } } })} \\ \\ y = \sqrt{x y} \\ \\ y^2 = x y \\ \\ y = x = 6 \\ [/tex]
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We can also do this in another way adding the powers of 6.
[tex]y = x^{\frac{1}{2}} * x^{\frac{1}{4}} * x^{\frac{1}{8}} * x^{\frac{1}{16}} * x^{\frac{1}{32}} * ...... \\ \\ It\ is \ an\ infinite \ geometric\ series\ with\ a=1/2\ and\ ratio=1/2 \\ \\ y = x^{ \frac{1}{2} + \frac{1}{4} + \frac{1}{8} + \frac{1}{16} ....} \\ \\ y = x^{\frac{1}{2}(\frac{1}{1-\frac{1}{2}})} \\ \\ y = x^{\frac{1}{2}*\frac{1}{\frac{1}{2}}} \\ \\ y = x = 6 \\ [/tex]
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We can also do this in another way adding the powers of 6.
[tex]y = x^{\frac{1}{2}} * x^{\frac{1}{4}} * x^{\frac{1}{8}} * x^{\frac{1}{16}} * x^{\frac{1}{32}} * ...... \\ \\ It\ is \ an\ infinite \ geometric\ series\ with\ a=1/2\ and\ ratio=1/2 \\ \\ y = x^{ \frac{1}{2} + \frac{1}{4} + \frac{1}{8} + \frac{1}{16} ....} \\ \\ y = x^{\frac{1}{2}(\frac{1}{1-\frac{1}{2}})} \\ \\ y = x^{\frac{1}{2}*\frac{1}{\frac{1}{2}}} \\ \\ y = x = 6 \\ [/tex]