Answer :
zeroes are 1 and 4
(x-1)(x-4)are factors
[tex]x^2-5x+4 [/tex] is a factor
on dividing,
we get quotient=[tex]x^2-3[/tex]
=[tex](x- \sqrt{3})(x+ \sqrt{3}) [/tex]
hence,√3 and -√3 are remaining zeroes
(x-1)(x-4)are factors
[tex]x^2-5x+4 [/tex] is a factor
on dividing,
we get quotient=[tex]x^2-3[/tex]
=[tex](x- \sqrt{3})(x+ \sqrt{3}) [/tex]
hence,√3 and -√3 are remaining zeroes
ATQ zeros are 1 and 4 therefore(x-1) and (x-4) are factor therefore x^2-5x+4 is a factor on dividing we quotient=x^2-3=(x-√3)(x+√3)