Answer :
the digitsum of the given number should be divisible by 3.
here the digitsum is=6+5+2+0+6+a=19+a.
after 19 the least number divisible by 3 is=21.
so, a=2.
here the digitsum is=6+5+2+0+6+a=19+a.
after 19 the least number divisible by 3 is=21.
so, a=2.
We know that if the sum of digits of a no. is divisible by 3 then it also divisible by 3.
Here,
6+5+2+0+a+6 = 19 + a
- Least possible value of a = 2.
Thank u.