Answer :
Maximum area enclosed with sides a, b, c, d of a quadrilateral
= √[ (s - a)(s - b)(s - c)(s - d) ] where s = (a + b + c + d) / 2.
Hence maximum area enclosed with pieces of given lengths
= √[ (5 - 1)(5 - 2)(5 - 3)(5 - 4) = √24 = 2√6
= √[ (s - a)(s - b)(s - c)(s - d) ] where s = (a + b + c + d) / 2.
Hence maximum area enclosed with pieces of given lengths
= √[ (5 - 1)(5 - 2)(5 - 3)(5 - 4) = √24 = 2√6