dweejareddy
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Five years hence , father's age will be three times the age of his son. Five years ago , father was seven times as old as his son . Find their present ages.

Answer :

TPS
let father's age = x
son's age = y

Five years hence, age of father = x+5 
                                 age of son = y+5
So (x+5) = 3(y+5)
⇒ x =3y+10

Five years ago, age of father = x-5 
                                 age of son = y-5
So x-5 = 7(y-5)
⇒3y + 10 - 5 = 7y - 35
⇒ 4y = 40
⇒y = 10  <<<<<<<<son's age
   x = 3y +10 = 40 <<<<<<father's age

VishalSharma01

Answer:

Step-by-step explanation:

Given :-

Five years hence, a man's age will be three times the age of his son.

Five years ago, the man was seven times as old as his son.

To Find  :-

Their Present ages

Solution :-

Let the present age of the man be x years

And His son's  be y years.  

1st Equation :-

After 5 years man’s age = x + 5  

After 5 years ago son’s age = y + 5  

According to the question  

⇒ x + 5 = 3(y + 5)

x – 3y = 10 ……………(i)  

2nd Equation

5 years ago man’s age = x – 5  

5 years ago son’s age = y – 5  

As per the question

⇒ x – 5 = 7(y – 5)

⇒ x – 7y = -30 …….(ii)

Subtracting (ii) from (i), we have  

⇒ 4y = 40  

⇒ y = 10  

Putting y value in Eq (i)

⇒ x – 3y = 10

⇒ x – 3 × 10 = 10  

⇒ x = 10 + 30

⇒ x = 40

Hence, man’s present age = 40 years and son’s present age = 10 years.

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